From Julian day to date - Printable Version

From Julian day to date - Printable Version

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+--- Thread: From Julian day to date (/showthread.php?tid=4283)

From Julian day to date - emme - 04.10.2022

Ciao to all,

I've made a small script that convert back the julian day to the specific date.

Using the

Code:
local cDate = os.date('*t') 

you can get the cDate.yday that represent the julian day (counting 1 from Jan 1st)

Apparentely there is no backformula that giving the year and the day, returns the complete date...

Well, I've made it:

Code:
function j2d(yd, aaaa)

  local mm, dd = 1, 1

  local cDate  = os.date('*t')

  local mdays  = {31,28,31,30,31,30,31,31,30,31,30,31}

  if not aaaa then aaaa = cDate.year end

  if aaaa % 4 == 0 then mdays[2] = 29 end

  for m = 1, 12 do

    if mdays[m] > yd then

      yd = yd - mdays[m]

      mm = m

    else

      dd = yd

      break

    end

  end

  yDate   = os.date('*t', os.time({year = aaaa, month = mm, day = dd}))

  yString = os.date('%d/%m/%Y',os.time({year = aaaa, month = mm, day = dd}))

  return yString, yDate

end

this functin can be saved into the common user function and be called by:

Code:
local cDate, tDate = j2d(270, 2022)

this will return the string for the date and the os.date('*t') table for the selected day...

hope this would help you somehow
ciao
M