31.10.2018, 14:03
Can be done like this:
Code:
OUTPUT = grp.find('1/0/108')
OUTPUT:write(false)|
Simple Script "less than" help
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Simple Script "less than" help - by Kai-Roger - 31.10.2018, 13:33
RE: Simple Script "less than" help - by admin - 31.10.2018, 13:40
RE: Simple Script "less than" help - by Kai-Roger - 31.10.2018, 13:45
RE: Simple Script "less than" help - by admin - 31.10.2018, 14:03
RE: Simple Script "less than" help - by Kai-Roger - 31.10.2018, 14:15
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