calculate diferent between years, month, days

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Here's my solution

Code:

sday, smonth, syear = 1, 2, 1999 eday, emonth, eyear = 2, 3, 2022 monthdiff = emonth - smonth yeardiff = eyear - syear daydiff = eday - sday if daydiff < 0 then   leap = ((eyear % 4 == 0) and (eyear % 100 ~= 0)) or (eyear % 400 == 0)   mdays = { 31, (leap and 29 or 28), 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 }   if emonth == 1 then     emonth = 12   else     emonth = emonth - 1   end   daydiff = daydiff + mdays[ emonth ]   monthdiff = monthdiff - 1 end if monthdiff < 0 then   monthdiff = monthdiff + 12   yeardiff = yeardiff - 1 end log(daydiff, monthdiff, yeardiff)