calculate diferent between years, month, days

[admin]

Here's my solution

Code:

sday, smonth, syear = 1, 2, 1999
eday, emonth, eyear = 2, 3, 2022

monthdiff = emonth - smonth
yeardiff = eyear - syear

daydiff = eday - sday
if daydiff < 0 then
  leap = ((eyear % 4 == 0) and (eyear % 100 ~= 0)) or (eyear % 400 == 0)
  mdays = { 31, (leap and 29 or 28), 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 }

  if emonth == 1 then
    emonth = 12
  else
    emonth = emonth - 1
  end

  daydiff = daydiff + mdays[ emonth ]
  monthdiff = monthdiff - 1
end

if monthdiff < 0 then
  monthdiff = monthdiff + 12
  yeardiff = yeardiff - 1
end

log(daydiff, monthdiff, yeardiff)