calculate diferent between years, month, days

[Dré]

Thanks, I choose to use the one of admin and changed it a little, so he calculates the different between today and the set day.
But both thanks for helping me.

Code:

now = os.date('*t')


eday = now.day
emonth = now.month
eyear = now.year

-- bevrijdingsdag
sday, smonth, syear = 5, 5, 1945

monthdiff = emonth - smonth
yeardiff = eyear - syear

daydiff = eday - sday
if daydiff < 0 then
  leap = ((eyear % 4 == 0) and (eyear % 100 ~= 0)) or (eyear % 400 == 0)
  mdays = { 31, (leap and 29 or 28), 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 }

  if emonth == 1 then
    emonth = 12
  else
    emonth = emonth - 1
  end

  daydiff = daydiff + mdays[ emonth ]
  monthdiff = monthdiff - 1
end

if monthdiff < 0 then
  monthdiff = monthdiff + 12
  yeardiff = yeardiff - 1
end

grp.checkupdate('62/7/51', yeardiff ..' jaar ' .. monthdiff ..' maanden ' .. daydiff ..' dagen ')