Sending and receiving in XML

[admin]

You can use lxp library to parse the XML:

Code:

xml = [[<?xml version="1.0" encoding="utf-8"?>
<stuMessages xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:noNamespaceSchemaLocation="http://cody.glpconnect.com/XSD/StuMessage_Rev1_0.xsd" timeStamp="27/08/2009
21:00:00 GMT" messageID="56bdca48088610048fddba385e1cd5b8">
<stuMessage>
<esn>0-99990</esn>
<unixTime>1034268516</unixTime>
<gps>N</gps>
<payload length="9" source="pc" encoding="hex">0xC0560D72DA4AB2445A</payload>
</stuMessage>
</stuMessages>
]]

require('lxp').new({
  StartElement = function(parser, tag, attrs)
    if tag == 'stuMessages' then
      timestamp = attrs.timeStamp
      messageid = attrs.messageID
    end
  end
}):parse(xml)

log(timestamp)
log(messageid)

There's no library for creating XML. For simple formats you can use raw strings:

Code:

timestamp = '27/08/2009 21:00:00 GMT'
messageid = '56bdca48088610048fddba385e1cd5b8'

xml = [[<?xml version="1.0" encoding="utf-8"?>
<stuResponseMsg xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:noNamespaceSchemaLocation="http://cody.glpconnect.com/XSD/StuResponse_Rev1_0.xsd"
deliveryTimeStamp="]] .. timestamp .. [[" correlationID="]] .. messageid .. [[">
<state>pass</state>
<stateMessage>Store OK</stateMessage>
</stuResponseMsg>]]