calculate diferent between years, month, days

[Erwin van der Zwart]

Not fully tested but something like this could work (however always tricky with leap years):

Code:

startdate = {
  day = 2,
  month = 9,
  year = 2006
}

enddate = {
  day = 16,
  month = 4,
  year = 2022
}

unixstart = os.time(startdate)
unixend = os.time(enddate)

if unixend < unixstart then
  log('Start date is higer then the end date, exiting script')
  return
end

seconds = os.difftime(unixend, unixstart)
timediff = os.date('!*t', seconds)

years = timediff.year - 1970
months = timediff.month - 1
days = timediff.day - 1

log(years,months,days)