Operating hours, relay closing time..., comparison 3byte

[sivlecrash]

Hello,
I have saved the on and off (time and date). Can you please advise me how to calculate the difference between "time_on, date_on" and "time_off, date_off" ?
Thank you

Code:

adr_relay_status     = '32/7/0'  --relay_status        --01 1bit
adr_time_on         = '32/7/1'  --on time            --10 3byte time/day
adr_date_on         = '32/7/2'  --on date            --11 3byte date
adr_time_off         = '32/7/3'  --off time            --10 3byte time/day
adr_date_off         = '32/7/4'  --off date            --11 3byte date
adr_sum_days         = '32/7/5'  --sum days            --07 2byte unsigned integer
adr_sum_hours         = '32/7/6'  --sum hours            --07 2byte unsigned integer
adr_sum_minutes     = '32/7/7'  --sum minutes        --07 2byte unsigned integer
adr_sum_seconds     = '32/7/8'  --sum seconds        --07 2byte unsigned integer


relay_status     = grp.getvalue(adr_relay_status)


if (relay_status == true) then
  -- get current data as table
  now = os.date('*t')
  -- system week day starts from sunday, convert it to knx format
  wday = now.wday == 1 and 7 or now.wday - 1
  -- time table
  time = {
  day = wday,
  hour = now.hour,
  minute = now.min,
  second = now.sec,
  }
  -- date table
  date = {
  day = now.day,
  month = now.month,
  year = now.year,
  }
  -- write to
  grp.write(adr_time_on, time, dt.time)
  grp.write(adr_date_on, date, dt.date)
end

if (relay_status == false) then
  -- get current data as table
  now = os.date('*t')
  -- system week day starts from sunday, convert it to knx format
  wday = now.wday == 1 and 7 or now.wday - 1
  -- time table
  time = {
  day = wday,
  hour = now.hour,
  minute = now.min,
  second = now.sec,
  }
  -- date table
  date = {
  day = now.day,
  month = now.month,
  year = now.year,
  }
  -- write to
  grp.write(adr_time_off, time, dt.time)
  grp.write(adr_date_off, date, dt.date)
 
  time_on     = grp.getvalue(adr_time_on)
  date_on     = grp.getvalue(adr_date_on)
  time_off     = grp.getvalue(adr_time_off)
  date_off     = grp.getvalue(adr_date_off)
  sum_days     = grp.getvalue(adr_sum_days)
  sum_hours     = grp.getvalue(adr_sum_hours)
  sum_minutes     = grp.getvalue(adr_sum_minutes)
  sum_seconds     = grp.getvalue(adr_sum_seconds)
 
  --[[
  script
  calculation of the difference between the on and off time of the relay
  addition to "sum_days" and  "sum_hours" and "sum_minutes" and "sum_seconds"
  ]]--
  days = 0 --?
  hours = 0 --?
  minutes = 0 --?
  seconds = 0 --?
 
  grp.write(adr_sum_days, days)
  grp.write(adr_sum_hours, hours)
  grp.write(adr_sum_minutes, minutes)
  grp.write(adr_sum_seconds, seconds)
end

[Daniel]

I'm not sure where you heading here but each object has its update time saved and you can use this instead os.time.

input = grp.find('1/1/1')
start = input.updatetime

This will give you time in numeric format. You can save on and off value in a storage and compare. Here is example of counter from FB Editor, It might help.

Code:

function operating_hours(input, reset, blockID)
  local inputValue = input.value and input.value ~= 0
  if reset and reset ~= 0 then
    if inputValue then
      storage.set(blockID .. "_start", os.time())
    end
    return inputValue and 0 or nil
  elseif inputValue then
    local start = storage.get(blockID .. "_start")
    if start == nil then
      start = input.updatetime
      storage.set(blockID .. "_start", start)
    end
    return (os.time() - start) / 3600
  else
    storage.delete(blockID .. "_start")
    return nil
  end
end




input = grp.find('1/1/1')
reset = grp.getvalue('1/1/4')
blockID= _SCRIPTNAME


hours = operating_hours(input, reset, blockID)
log(hours)
if hours ~= nil then
    grp.write('1/1/2', hours)
end

[sivlecrash]

Thank you. I will try.