Hi
After some testing I discovered that when sending an email to multiple recipients the 'to' variable wasn't being converted to an table. It would create a table but only contained one row. Below is a revised version of the send email script. Make sure that each recipient is separated with a comma, ie... mail('your@first.com, your@second.com, your@third.com', 'some subject', 'some message')
In addition to this, when you want to send via an email server that does not require ssl, just comment out the line, secure='sslv23'
Thanks,
Roger
After some testing I discovered that when sending an email to multiple recipients the 'to' variable wasn't being converted to an table. It would create a table but only contained one row. Below is a revised version of the send email script. Make sure that each recipient is separated with a comma, ie... mail('your@first.com, your@second.com, your@third.com', 'some subject', 'some message')
In addition to this, when you want to send via an email server that does not require ssl, just comment out the line, secure='sslv23'
Thanks,
Roger
Code:
-- send an e-mail
function mail(to, subject, message)
-- make sure these settings are correct
local settings = {
-- "from" field, only e-mail must be specified here
from = 'example@gmail.com',
-- smtp username
user = 'example@gmail.com',
-- smtp password
password = 'mypassword',
-- smtp server
server = 'smtp.gmail.com',
-- smtp server port
port = 465,
-- enable ssl, required for gmail smtp
secure = 'sslv23',
}
local smtp = require('socket.smtp')
if type(to) ~= 'table' then
to = string.split(to,', ')
end
for index, email in ipairs(to) do
to[ index ] = '<' .. tostring(email) .. '>'
end
-- message headers and body
settings.source = smtp.message({
headers = {
to = table.concat(to, ', '),
subject = subject,
['Content-type'] = 'text/html; charset=utf-8',
},
body = message
})
-- fixup from field
settings.from = '<' .. tostring(settings.from) .. '>'
settings.rcpt = to
return smtp.send(settings)
end