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1 script 200 Rooms
#6
Here's a solution with a lookup table. All input objects should have a common tag to which an event script is attached. Fill the addrlist table with group addresses as needed. Each entry is a single room (input 1/2 + output).

The script finds the second input based on the group address that triggered the script and writes the maximum between two inputs to the output object.
Code:
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addrlist = {   {     input1 = '1/1/1',     input2 = '1/1/2',     output = '1/1/3',   },   {     input1 = '1/1/4',     input2 = '1/1/5',     output = '1/1/6',   },   {     input1 = '1/2/4',     input2 = '1/2/5',     output = '1/2/6',   }, } for _, addrs in ipairs(addrlist) do   if event.dst == addrs.input1 then     altinput = addrs.input2     output = addrs.output     break   elseif event.dst == addrs.input2 then     altinput = addrs.input1     output = addrs.output     break   end end if altinput and output then   value1 = event.getvalue()   value2 = grp.getvalue(altinput)   grp.checkwrite(output, math.max(value1, value2)) end
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Messages In This Thread
1 script 200 Rooms - by Stuart2000 - 12.04.2022, 08:49
RE: 1 script 200 Rooms - by admin - 12.04.2022, 08:55
RE: 1 script 200 Rooms - by Stuart2000 - 12.04.2022, 09:05
RE: 1 script 200 Rooms - by admin - 12.04.2022, 09:17
RE: 1 script 200 Rooms - by Stuart2000 - 12.04.2022, 16:30
RE: 1 script 200 Rooms - by admin - 13.04.2022, 11:21
RE: 1 script 200 Rooms - by Stuart2000 - 19.04.2022, 06:03

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